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Posts

Viewing 1 to 20 (55 Total)

re: using same jquery on two different article tags on same page

Can you attach your html markup to the post.

Posted on April 16, 2012 at 9:14 PM

re: AJAX, PHP Form Submission

Change url: '../template/includes/process_quote.php' to url: '/template/includes/process_quote.php' in the AJAX request and see if that works. Your getting a 403 forbidden error so your either looking in the wrong place for the php script or you don't have permissions to access it.

Posted on March 17, 2012 at 9:42 AM

re: Ajax PHP form submission....

not sure why you're not getting the success message, but you can fix the from name by adding a 5th parameter to the mail function
mail(param1, param2, param3, param4, "-femail@yourdomain.com")

Posted on January 26, 2012 at 12:38 PM

re: Ajax PHP form submission....

Weird....try calling exit(); within the if portion of the mail check.
if(mail(ect, ect, ect, ect)) {
return stuff here
exit();
}else
other stff
}

Posted on January 26, 2012 at 12:04 PM

re: Ajax PHP form submission....

See if the attached file takes care of your problem shades

Attachments: bookingsform-mod.txt
Posted on January 26, 2012 at 11:04 AM

re: Ajax PHP form submission....

Thanks for the kind words my friend grin . Paste your php code in a txt file and attach it to your post, it seems like that is where the error is.

Posted on January 26, 2012 at 6:33 AM

re: Firefox bug - Multiple dropdown content changing with previous selection

Nice site btw, looks like your off to a really nice start shades

Posted on January 09, 2012 at 7:01 PM

re: Firefox bug - Multiple dropdown content changing with previous selection

I'm not sure exactly what the problem is other than at line 86 of scripts.js the variable your storing a value in is returning undefined and so when you're try to use the split method on your undefined variable it's throwing an error and Firefox won't continue. "this" is not what you think it is in that context.

Hope that points you in the right direction.

Posted on January 09, 2012 at 7:00 PM

re: SyntaxError: JSON.parse: unexpected character parsererror

Glad you found the error, sorry I wasn't any help.smiling

Posted on January 07, 2012 at 9:36 AM

re: SyntaxError: JSON.parse: unexpected character parsererror

What version of the jQuery library are you using?

Posted on December 20, 2011 at 4:26 PM

re: Jquery Accordion Navigation

It's not you saneloski, I haven't finished with the syntax highlighter. If you have a lot of code just paste it into a txt file and attach that to your post my friend.

Posted on November 17, 2011 at 5:43 PM

re: jQuery tabContainers problem after upgrading to WordPress 3.2.1

Weird, do you have a link that we can check out?

Posted on November 09, 2011 at 12:51 PM

re: AJAX form submission using jQuery and PHP

Yeah sounds like a permissions issue.

Posted on November 04, 2011 at 4:16 PM

re: AJAX form submission using jQuery and PHP

Sounds like you don't have access to the directory you were trying to access, but I can't be sure man. Is this a windows or Linux server?

Posted on November 03, 2011 at 4:55 PM

re: Simple Slide Show Using jQuery Fade Effect will only cycle first image on making into a link

No problem my friend, glad to help. Don't be a stranger.

Posted on November 03, 2011 at 4:51 PM

re: Simple Slide Show Using jQuery Fade Effect will only cycle first image on making into a link

Modified your file and attached. Hope that gets you fixed up.shades

Attachments: solution.txt
Posted on November 02, 2011 at 5:50 PM

re: AJAX form submission using jQuery and PHP

is $textarea a variable?
var textarea = $('textarea').val();
if(empty(textarea) || textarea.val() == '')

Posted on November 01, 2011 at 4:15 PM

re: AJAX form submission using jQuery and PHP

Sorry my friend, I don't understand you question.

Posted on October 31, 2011 at 5:26 PM

re: AJAX form submission using jQuery and PHP

You'll need to get the values of each and compare them as well as checking that they are not blank.
var pw = $('password-id').val();
var pwC = $('password-confirm-id').val();
if (pw != '' && pwC != '') {
if(pw != pwC) {
valid += 'Your password do not match';
}
}

That should get you on the right track.

Posted on October 29, 2011 at 9:22 AM

re: Simple Slide Show Using jQuery Fade Effect will only cycle first image on making into a link

No problem, glad to help!shades

Posted on October 20, 2011 at 5:25 PM
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